I am infuriating to design a titration to find the concentration of '100 volume' H2O2 but to do my calculations constraint to know the value of 100 volume in moldm^-3.

2H2O2 --> 2H2O + O2
100 vol means that 1 cm3 of the answer produces 100 cm3 of oxygen gas.
At r.t. 1 mole of a gas occupies 24000 cm3
So 100 cm3 contains 100/24000 = 4.2 X 10^-3 mol of oxygen
So 1 cm3 of the H2O2 answer contains 8.

CB | May 10, 2009

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The oxygen gas will be unruffled and solemn by using gas syringe. As a run-of-the-mill gas syringe holds about 100cm3, a attractive amount of oxygen to get would be about 60cm3. 10-volume H2O2 liberates 10cm3 of oxygen for every 1cm3 of H2O2 and so therefore 6cm3 of H2O2 will be required.

Source: Check Concentration Calculation (Very Wordy As For Coursework)

[Chemistry] Determine the concentration of h2o2 by redox titration!

You are provided with a answer of hydrogen peroxide which is known to be about ‘100-volume’. System two experiments that would permit you to upon the rigid concentration of H2O2 in mol dm-3, in this settling. One of your experiments should catch up in a redox titration with potassium manganate (VII). The other policy test should not entangle a titration. Hi Borek, I was wondering if you could assist me. I'm doing the titration of H2O2 with KMnO4 in up to settle the concentration of H2O2. I be in sympathy with that H2SO4 is required in the response, now if I break into the KMnO4 in H2SO4 does that upon rely on? Also, if I melt into 2.5g of sober KMnO4 in 47.5cm3 of H2SO4. Will this be the resulting concentration?

Source: [Chemistry] Determine the concentration of h2o2 by redox titration!